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Guidelines to find the atomic positions


Here we will present some guidelines to find the atomic positions of a unknown compound and we will take the example of the compound CaCl2.


1- Look for the space group of the compound (there may be more than one space group for the compound) .

For the compound CaCl2 the space group is Pnnm with # 58. Now we will find the different Wyckoff Positions of the space group Pnnm from the site http://www.cryst.ehu.es/cgi-bin/cryst/programs/nph-wp-list 



Wyckoff Positions of Group 58 (Pnnm)

MultiplicityWyckoff
letter
Site
symmetry
Coordinates
8h1
(x,y,z)(-x,-y,z)(-x+1/2,y+1/2,-z+1/2)(x+1/2,-y+1/2,-z+1/2)
(-x,-y,-z)(x,y,-z)(x+1/2,-y+1/2,z+1/2)(-x+1/2,y+1/2,z+1/2)
4g..m
(x,y,0)(-x,-y,0)(-x+1/2,y+1/2,1/2)(x+1/2,-y+1/2,1/2)
4f..2
(0,1/2,z)(1/2,0,-z+1/2)(0,1/2,-z)(1/2,0,z+1/2)
4e..2
(0,0,z)(1/2,1/2,-z+1/2)(0,0,-z)(1/2,1/2,z+1/2)
2d..2/m
(0,1/2,1/2)(1/2,0,0)
2c..2/m
(0,1/2,0)(1/2,0,1/2)
2b..2/m
(0,0,1/2)(1/2,1/2,0)
2a..2/m
(0,0,0)(1/2,1/2,1/2)


2- We look for a similar compound with the same space group Pnnm

We have found the compound FeSe2 with the crystal structure in format cif from here Crystal structure of FeSe2

       x                        y                             z

Fe   0                       0                              0

Se   0.212700       0.370100             0


We conclude from this that the x,y and z of Fe are always zero which are equivalent to the whyckoff position 2a and the x and y of Se are free parameters while z is always zero with are equivalent to the whyckoff position 4g. We can verify that the molecule FeSe2 is formed with one atom of Fe and two atoms of Se.

3- Now we need to define the x and y values for Cl

We can use the atomic positions of a compound of similar compound with close atomic number and then optimize them to get the real values for this compound


Result:

Ca (2a)  0   0   0

Cl  (4g)  x   y   0    with  x and y having free values similar to 0.21 and 0.37

1 comment:

  1. How do you determine GaAs and Si coordinates following the same process? Would you please explain a little bit?

    ReplyDelete

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